化合物よくある質問
N-(1H-咪唑-2-基甲基)-4-氯苯胺はどのように合成されますか？
回答
![4-Chloro-N-[(1H-imidazol-2-yl)methyl]aniline](https://static.chemtradehub.com/structs/166/166096-16-8-b841.webp "4-Chloro-N-[(1H-imidazol-2-yl)methyl]aniline")
N-(1H-咪唑-2-基甲基)-4-氯苯胺は、4-塩基化アミノ苯と2-ヒドロキシ-1H-イミダゾールを反応させて、塩基性条件下でN-アミド化を促進します。収率は約90％です。
について
CAS番号
166096-16-8
英語名前
4-Chloro-N-[(1H-imidazol-2-yl)methyl]aniline
分子式
C10H10ClN3
分子量
207.66400000000002 g/mol
SMILES
C1=CC(=CC=C1NCC2=NC=CN2)Cl
InChIKey
SIFYJEQOTXUWFR-UHFFFAOYSA-N
最後の更新: 2026-01-01 15:35
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